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merge_two_sorted_lists_21.py
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merge_two_sorted_lists_21.py
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"""
You are given the heads of two sorted linked lists list1 and list2.
Merge the two lists into one sorted list. The list should be made by splicing together the nodes of the first two lists.
Return the head of the merged linked list.
Example 1:
Input: list1 = [1,2,4], list2 = [1,3,4]
Output: [1,1,2,3,4,4]
Example 2:
Input: list1 = [], list2 = []
Output: []
Example 3:
Input: list1 = [], list2 = [0]
Output: [0]
Constraints:
The number of nodes in both lists is in the range [0, 50].
-100 <= Node.val <= 100
Both list1 and list2 are sorted in non-decreasing order.
"""
from typing import Optional
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
class Solution:
def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]:
merge_node = ListNode(0)
result = merge_node
while list1 and list2:
if list1.val < list2.val:
merge_node.next = ListNode(list1.val)
list1 = list1.next
else:
merge_node.next = ListNode(list2.val)
list2 = list2.next
merge_node = merge_node.next
while list1:
merge_node.next = ListNode(list1.val)
list1 = list1.next
merge_node = merge_node.next
while list2:
merge_node.next = ListNode(list2.val)
list2 = list2.next
merge_node = merge_node.next
return result.next
def create_linked_list(lst):
head = ListNode(0)
current = head
for value in lst:
current.next = ListNode(value)
current = current.next
return head.next
def to_list(node):
lst = []
while node:
lst.append(node.val)
node = node.next
return lst
if __name__ == '__main__':
solution = Solution()
assert to_list(solution.mergeTwoLists(create_linked_list([1, 2, 4]), create_linked_list([1, 3, 4]))) == [1, 1, 2, 3, 4, 4], "Error on test case 1"
assert to_list(solution.mergeTwoLists(create_linked_list([]), create_linked_list([]))) == [], "Error on test case 2"
assert to_list(solution.mergeTwoLists(create_linked_list([]), create_linked_list([0]))) == [0], "Error on test case 3"
print("All tests passed successfully.")