Evaluate an attribute against a member of a set

[haikalpribadi]

Problem to Solve

We would like to query a pattern that evaluates the value of an attribute against a member of a set. For example:

match $x isa person, has occupation in ["working", "student", "unemployed"];

Current Workaround

Multiple disjunctions of attribute evaluations.

Proposed Solution

match $x isa person, has occupation in ["working", "student", "unemployed"];

Additional Information

To be further designed: How to assign a variable to the attribute?

[lveillard]

Another current workaround we use is using 'link' with an ugly regex 'valueA|valueB|ValueC'
But with obvious performance impacts, so eager to get this 'in' clause.

It would be also nice to be able to use "in" to create subsets, for instance

$a ($players) isa authorship;
$b isa reviewer;
$c is {$b in $players}

This example is workaroundable, but other more complex use cases are not. I'm just showing this one as it is easier to understand.