Feature Request of webclient : getRedirectedUri()

[purplepapa]

I am using web client to get urls . I need to get the redirected uri for further parsing as base url . Thanks in advance . As I investigated, HttpAsyncClient uses a HttpContext to get it:

CloseableHttpAsyncClient httpclient = HttpAsyncClients.custom().build();
            try {
                httpclient.start();
                HttpClientContext localContext = HttpClientContext.create();
                HttpGet request = new HttpGet("https://bit.ly/1eTpSHp");
                request.setHeader("User-Agent", "gis");
                Future<HttpResponse> future = httpclient.execute(request, localContext, null);
                HttpResponse response = future.get();
                String result = IOUtils.toString(response.getEntity().getContent(), StandardCharsets.UTF_8);
                System.out.println("Response: " + response.getStatusLine().getStatusCode() + ":" + result.length());
                HttpHost target = localContext.getTargetHost();
                List<URI> redirectLocations = localContext.getRedirectLocations();
                for (URI u : redirectLocations) {
                    System.out.println("location: " + u.toASCIIString());
                }
                URI location = URIUtils.resolve(request.getURI(), target, redirectLocations);
                System.out.println("Final HTTP location: " + location.toASCIIString());
                // Expected to be an absolute URI
            } finally {
                httpclient.close();
            }

just for reference.

[slinkydeveloper]

I've opened a pr for it: #1291