Given the head
of a sorted linked list, delete all duplicates such that each element appears only once. Return the linked list sorted as well.
Input: head = [1,1,2]
Output: [1,2]
Input: head = [1,1,2,3,3]
Output: [1,2,3]
- The number of nodes in the list is in the range
[0, 300]
. -100 <= Node.val <= 100
- The list is guaranteed to be sorted in ascending order.
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def deleteDuplicates(self, head: ListNode) -> ListNode:
ans = ListNode(-101, head)
ptr = ans
latest = ans
while ptr.next:
ptr = ptr.next
if ptr.val != latest.val:
latest.next = ptr
latest = latest.next
latest.next = None
return ans.next
Even simpler linked list manipulation.