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BestTimeToBuy&Sell.cpp
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BestTimeToBuy&Sell.cpp
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You are given an array prices where prices[i] is the price of a given stock on the ith day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
Example 1:
Input: prices = [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
Example 2:
Input: prices = [7,6,4,3,1]
Output: 0
Explanation: In this case, no transactions are done and the max profit = 0.
//SOLUTION GIVEN BELOW
//Description -> any Stock buy and sell at a time not multiples time
class Solution {
public:
int maxProfit(vector<int>& prices) {
int mini = prices[0]; // mininum , from starting
int profit = 0;
for(int i = 1;i< prices.size();i++){ // Interate all days
int diff = prices[i] - mini; // differnece
profit = max(profit , diff); // update profit
mini = min(mini , prices[i]); //update mini
}
return profit;
}
};