test that id() == hash() is not safe across architectures

[llimeht]

Hi!

When executing the test suite on 32 bit architectures (Debian's i386 and armhf), the test suite fails with an architecture specific error:

FAIL: test__mock_hashability (tests.test__mocking_instances.MockingTest)
----------------------------------------------------------------------
Traceback (most recent call last):
  File "/build/1st/python-pyforge-1.3.0/.pybuild/pythonX.Y_2.7/build/tests/test__mocking_instances.py",     line 19, in test__mock_hashability
    self.assertEquals(id(self.obj), hash(self.obj))
AssertionError: 3057633680L != -1237333616

The difference in these values is 2^32. From the python documentation, if __hash__ returns a long, then that long may be further hashed to produce a 32 bit integer which appears to be what is happening here, where id() is returning longs on 32 bit archs but not on 64 bit archs.

https://docs.python.org/2/reference/datamodel.html#object.__hash__

Overall, this test appears to be testing the internals of the interpreter and not turning the hashing on/off as desired. Would a better test be to check that a TypeError is not raised?

64 bit Python

(sid_amd64-dchroot)$ python
Python 2.7.12+ (default, Nov  4 2016, 17:04:30) 
[GCC 6.2.0 20161027] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> class Foo():
...     def __hash__(self):
...         return id(self)
... 
>>> f = Foo()
>>> id(f)
140149834025872
>>> hash(f)
140149834025872
>>> 

32 bit Python

(sid_i386-dchroot)$ python
Python 2.7.12+ (default, Nov  4 2016, 17:04:30) 
[GCC 6.2.0 20161027] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> class Foo():
...     def __hash__(self):
...         return id(self)
... 
>>> f = Foo()
>>> id(f)
4143861580L
>>> hash(f)
-151105716
>>>

[vmalloc]

Ack. Will fix. Thanks for reporting!

[vmalloc]

Removed the specific check. Didn't really serve any purpose.