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FLOW1.cpp
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FLOW1.cpp
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#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int,int> ii;
typedef unsigned long long ull;
#define X first
#define Y second
#define pb push_back
#define mp make_pair
#define ep emplace_back
#define EL printf("\n")
#define sz(A) (int) A.size()
#define FOR(i,l,r) for (int i=l;i<=r;i++)
#define FOD(i,r,l) for (int i=r;i>=l;i--)
#define fillchar(a,x) memset(a, x, sizeof (a))
#define faster ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
const int N = 1100, inf = 1e9;
int n, m, k, s, t, lab[3][N];
int f[N][N], c[N][N], trace[N], dmin[N];
vector<int> a[N];
vector<int> Input() {
string s;
getline(cin, s);
vector<int> a;
for (int i = 0; i < s.size(); ) {
int x = 0;
while (i < s.size() && s[i] == ' ') ++i;
while (i < s.size() && s[i] != ' ')
x = x * 10 + s[i++] - '0';
if (x) a.pb(x);
}
return a;
}
void solve(int group) {
FOR(i,1,n) {
lab[group][i] = ++k;
vector<int> adj = Input();
for (auto j : adj) {
if (group == 1)
a[k].pb(j), a[j].pb(k), c[k][j] = 1;
else
a[k].pb(j+m), a[j+m].pb(k), c[j+m][k] = 1;
}
}
}
void Add(int &s, int group) {
s = ++k;
FOR(i,1,n) {
int t = lab[group][i];
a[s].pb(t);
a[t].pb(s);
if (group == 1) c[s][t] = 1;
else c[t][s] = 1;
}
}
void init() {
k = m * 2;
FOR(i,1,m) {
int j = i + m;
a[i].pb(j);
a[j].pb(i);
c[i][j] = 1;
}
solve(1);
solve(2);
Add(s,1);
Add(t,2);
}
bool findPath() {
FOR(i,1,k) dmin[i] = inf, trace[i] = 0;
trace[s] = -1;
queue<int> st;
st.push(s);
while (! st.empty()) {
int u = st.front();
st.pop();
for (auto v : a[u]) {
if (trace[v] == 0 && c[u][v] > f[u][v]) {
trace[v] = u;
dmin[v] = min(dmin[u], c[u][v] - f[u][v]);
if (v == t) return true;
st.push(v);
}
}
}
return false;
}
int main() {
// freopen("INP.TXT", "r", stdin);
// freopen("OUT.TXT", "w", stdout);
scanf("%d%d\n", &n,&m);
init();
while (findPath()) {
int v = t, del = dmin[t];
while (v != s) {
int u = trace[v];
f[u][v] += del;
f[v][u] -= del;
v = u;
}
}
FOR(i,1,m) {
int j = i + m, u = 0, v = 0, e = 0;
FOR(q,1,n) {
e = lab[1][q];
if (f[e][i] > 0) u = q;
e = lab[2][q];
if (f[j][e] > 0) v = q;
if (u && v) break;
}
printf("%d %d\n", u, v);
}
return 0;
}