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first course assignment
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first course assignment
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#include<cstdio>
#include<algorithm>
#include<cmath>
#include<cstring>
using namespace std;
/*
10 30
1 2 5
1 3 7
1 5 6
1 6 20
1 8 12
1 9 23
1 10 13
2 4 15
2 5 17
2 6 8
2 7 19
2 9 37
3 5 21
3 4 33
3 8 29
3 7 12
3 10 18
4 7 16
4 10 39
4 6 26
5 7 26
5 9 7
5 10 17
6 7 18
6 8 24
6 10 16
7 8 22
7 10 19
8 9 7
9 10 28
*/
int head[110], ecnt = 0;
struct Edge {
int from, to, nxt, val;
Edge() {};
Edge(int from, int to, int nxt, int val) : from(from), to(to), nxt(nxt), val(val) {};
bool operator < (const Edge& a) const {
return val < a.val;
}
}edge[110 * 10];
inline void add(int u, int v, int w) {
edge[++ecnt] = { u, v, head[u], w }; head[u] = ecnt;
edge[++ecnt] = { v, u, head[v], w }; head[v] = ecnt;
}
bool vis[110];
int dis[110];
int prim(int s, int n) {
printf("prim: start is %d\n", s);
int sum = 0;
memset(dis, 0x3f, sizeof dis);
for (int i = head[s]; i; i = edge[i].nxt) {
dis[edge[i].to] = edge[i].val;
}
vis[s] = 1;
while (1) {
int k = -1, minn = 0x3f3f3f3f;
for (int i = 1; i <= n; ++i) {
if (vis[i]) continue;
if (minn > dis[i]) {
minn = dis[i]; k = i;
}
}
if (k == -1) break;
vis[k] = 1; sum += minn;
printf("%d %d\n", k, minn);
for (int i = head[k]; i; i = edge[i].nxt) {
if (vis[edge[i].to]) continue;
dis[edge[i].to] = min(dis[edge[i].to], edge[i].val);
}
}
return sum;
}
int fa[110];
int find(int x) {
if (fa[x] != x) fa[x] = find(fa[x]);
return fa[x];
}
void union_(int x, int y) {
int fx = find(x), fy = find(y);
if (fx != fy) fa[x] = y;
}
int kruskal(int n) {
puts("kruskal:");
sort(edge, edge + ecnt);
int cnt = 0, sum = 0;
for (int i = 1; i <= n; ++i) fa[i] = i;
for (int i = 0; i < ecnt; ++i) {
if (find(edge[i].to) != find(edge[i].from)) {
printf("%d %d %d\n", edge[i].from, edge[i].to, edge[i].val);
cnt++; sum += edge[i].val;
union_(edge[i].to, edge[i].from);
}
if (cnt == n - 1) break;
}
return sum;
}
int main() {
int n, m; scanf("%d %d", &n, &m);
for (int i = 0; i < m; ++i) {
int u, v, w;
scanf("%d %d %d", &u, &v, &w);
add(u, v, w);
}
printf("%d\n", prim(1, n));
printf("%d\n", kruskal(n));
}