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704. 二分查找 #57

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webVueBlog opened this issue Sep 12, 2022 · 0 comments
Open

704. 二分查找 #57

webVueBlog opened this issue Sep 12, 2022 · 0 comments

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@webVueBlog
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704. 二分查找

Description

Difficulty: 简单

Related Topics: 数组, 二分查找

给定一个 n 个元素有序的(升序)整型数组 nums 和一个目标值 target  ,写一个函数搜索 nums 中的 target,如果目标值存在返回下标,否则返回 -1

示例 1:

输入: nums = [-1,0,3,5,9,12], target = 9
输出: 4
解释: 9 出现在 nums 中并且下标为 4

示例 2:

输入: nums = [-1,0,3,5,9,12], target = 2
输出: -1
解释: 2 不存在 nums 中因此返回 -1

提示:

  1. 你可以假设 nums 中的所有元素是不重复的。
  2. n 将在 [1, 10000]之间。
  3. nums 的每个元素都将在 [-9999, 9999]之间。

Solution

Language: JavaScript

/**
 * @param {number[]} nums
 * @param {number} target
 * @return {number}
 */
// 二分查找
var search = function(nums, target) {
    let left = 0, right = nums.length - 1
    while (left <= right) {
        const mid = Math.floor((right - left) / 2) + left
        const num = nums[mid]
        if (num === target) {
            return mid
        } else if (num > target) {
            right = mid - 1
        } else {
            left = mid + 1
        }
    }
    return -1
};
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