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The original answer is wrong when x>y>z
The answer may be #define MEDIAN(x,y,z) (((x)>(y)&&(x)<(z))||((x)<(y)&&(x)>(z)))?(x):(((y)>(x)&&(y)<(z))||((y<x)&&(y>z)))?(y):(z)
The text was updated successfully, but these errors were encountered:
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The original answer is wrong when x>y>z
The answer may be
#define MEDIAN(x,y,z) (((x)>(y)&&(x)<(z))||((x)<(y)&&(x)>(z)))?(x):(((y)>(x)&&(y)<(z))||((y<x)&&(y>z)))?(y):(z)
The text was updated successfully, but these errors were encountered: