Question: Send PartyInvitation on IncomingPendingFriend

[kaaax0815]

Sorry that this is not an issue, but im curious tho.

I cant find any API for sending an invitation in the fortnitepy docs

So I ask you how to send and PartyInvitation on an IncomingPendingFriend

Edit:

fortnite.py.Friend invite() is the right thing

New Problem:

How do I set the name to IncomingPendingFriend.display_name

Edit2:

Code: await fortnitepy.Friend.invite( display_name=request.display_name )

Error: Task exception was never retrieved future: <Task finished coro=<event_friend_request() done, defined at fortnite.py:257> exception=TypeError("invite() got an unexpected keyword argument 'display_name'")> Traceback (most recent call last): File "fortnite.py", line 264, in event_friend_request display_name=request.display_name TypeError: invite() got an unexpected keyword argument 'display_name'

It says that display_name is unexpected, but how else should i define the receiver

[xMistt]

You need to get an instance of the friend object, if you accept a pending friend request, the method itself returns the newly created Friend object so you can do:

friend = await pending.accept()
await friend.invite()

Hope this helps!