count-and-say.py

# Time:  O(n * 2^n)
# Space: O(2^n)
#
# The count-and-say sequence is the sequence of integers beginning as follows:
# 1, 11, 21, 1211, 111221, ...
# 
# 1 is read off as "one 1" or 11.
# 11 is read off as "two 1s" or 21.
# 21 is read off as "one 2, then one 1" or 1211.
# Given an integer n, generate the nth sequence.
# 
# Note: The sequence of integers will be represented as a string.
#

class Solution:
    # @return a string
    def countAndSay(self, n):
        seq = "1"
        for i in xrange(n - 1):
            seq = self.getNext(seq)
        return seq
    
    def getNext(self, seq):
        i, next_seq = 0, ""
        while i < len(seq):
            cnt = 1        
            while i < len(seq) - 1 and seq[i] == seq[i + 1]:
                cnt += 1
                i += 1
            next_seq += "{}{}".format(cnt, seq[i])
            i += 1
        return next_seq

if __name__ == "__main__":
    for i in xrange(1, 4):
        print Solution().countAndSay(i)