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const char[]をconst char*の代わりに使う。 #2

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xkikeg opened this issue Nov 21, 2011 · 0 comments
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const char[]をconst char*の代わりに使う。 #2

xkikeg opened this issue Nov 21, 2011 · 0 comments
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xkikeg commented Nov 21, 2011

文字通り。

const char hoge[] = "AA";

は

const char * hoge = "AA";

より効率がいいらしい。
@ghost ghost assigned xkikeg Nov 24, 2011
@xkikeg xkikeg closed this as completed Nov 30, 2011
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