package org.nocoder.leetcode.solution;
import java.util.HashSet;
import java.util.Set;
import java.util.regex.Pattern;
/**
* Every email consists of a local name and a domain name, separated by the @ sign.
* <p>
* For example, in `alice@leetcode.com`, `alice` is the local name, and `leetcode.com` is the domain name.
* <p>
* Besides lowercase letters, these emails may contain `'.'`s or `'+'`s.
* <p>
* If you add periods (`'.'`) between some characters in the **local name** part of an email address,
* mail sent there will be forwarded to the same address without dots in the local name.
* For example, `"alice.z@leetcode.com"` and `"alicez@leetcode.com"` forward to the same email address.
* (Note that this rule does not apply for domain names.)
* <p>
* If you add a plus (`'+'`) in the **local name**, everything after the first plus sign will be **ignored**.
* This allows certain emails to be filtered, for example `m.y+name@email.com` will be forwarded to `my@email.com`.
* (Again, this rule does not apply for domain names.)
* <p>
* It is possible to use both of these rules at the same time.
* <p>
* Given a list of `emails`, we send one email to each address in the list.
* How many different addresses actually receive mails?
* <p>
* <p>
* <p>
* **Example 1:**
* <p>
* ```shell
* Input: ["test.email+alex@leetcode.com","test.e.mail+bob.cathy@leetcode.com","testemail+david@lee.tcode.com"]
* Output: 2
* Explanation: "testemail@leetcode.com" and "testemail@lee.tcode.com" actually receive mails
* ```
* <p>
* **Note:**
* <p>
* - `1 <= emails[i].length <= 100`
* - `1 <= emails.length <= 100`
* - Each `emails[i]` contains exactly one `'@'` character.
*
* @author yangjinlong
* @date 2019-01-02
*/
public class UniqueEmailAddress {
public int numUniqueEmails(String[] emails) {
if (emails == null || emails.length > 100) {
throw new IllegalArgumentException();
}
String pattern = "^\\w+([-+.]\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*$";
Set emailSet = new HashSet();
for (int i = 0; i < emails.length; i++) {
if (Pattern.matches(pattern, emails[i])) {
int plusIdx = emails[i].indexOf("+");
int atIdx = emails[i].indexOf("@");
String ignoreContent = emails[i].substring(plusIdx, atIdx);
String email = emails[i].replace(ignoreContent, "");
String localName = email.substring(0, email.indexOf("@"));
String domainName = email.substring(email.indexOf("@"), email.length() - 1);
email = localName.replace(".", "").concat(domainName);
emailSet.add(email);
}
}
return emailSet.size();
}
public static void main(String[] args) {
String[] emails = new String[]{"test.email+alex@leetcode.com", "test.e.mail+bob.cathy@leetcode.com", "testemail+david@lee.tcode.com"};
UniqueEmailAddress uniqueEmailAddress = new UniqueEmailAddress();
int n = uniqueEmailAddress.numUniqueEmails(emails);
System.out.println(n);
}
}https://netty.io/wiki/user-guide-for-4.x.html#wiki-h2-0
python 爬取当当图书信息
import requests
from bs4 import BeautifulSoup
from fake_useragent import UserAgent
def crawl_book_info(isbn):
agent = UserAgent()
headers = {'User-Agent': agent.random}
url = 'http://search.dangdang.com/?act=input&key=' + isbn
data = requests.get(url, headers=headers)
soup = BeautifulSoup(data.text, 'lxml')
ul = soup.find_all('ul', {'class': 'bigimg'})
title = ''
image = ''
if len(ul) > 0:
li = ul[0].find_all('li')
if len(li) > 0:
title = li[0].find('a').get('title')
image = li[0].find('img').get('src')
return title, isbn, image假如你是个医生，病人要求你在手术前不要洗手，因为病人认为洗手太耽误时间了，你会照做吗。当然不会，因为医生是专业的，知道病菌的危害有多大，手术风险有多大。同理，程序员盲目遵从不明风险的经理的要求，也是不专业的。 --《Clean Code》
如果你让你自己陷入忙忙忙的境地，你要特别小心了。你没有时间好好思考，你就不会成长，你就不会渐渐做出调整，你就可能无法适应外面的世界，你就会在危机来临时不堪一击。... 保持思考的习惯，思考一些大的东西。「打小算盘」并不是有价值的思考。--蔡学镛