数组去重

[yijinc]

example

• 输入：[1,'1',1]， 则输出： [1,'1']
• 输入：[{a: 1}, {b: 1}, {a: 1}]， 则输出：[{a: 1}, {b: 1}]
• 输入：[{a: 1}, {b: 1}, {a: 1}]， 则输出：[{a: 1}, {b: 1}]
• 输入：[{a: 1, b: 2}, {b: 1}, {b: 2, a: 1}]， 则输出：[{a: 1, b: 2}, {b: 1}]
• 输入：[[1, {a: 1}], [2], [3], [1, {a: 1}]]， 则输出： [[1, {a: 1}], [2], [3]]

[yijinc]

function unique(arr) {
    const isEqual = (a, b) => {
        if (Array.isArray(a) && Array.isArray(b)) {
            return a.every((item, index) => isEqual(item, b[index]));
        }
        if (typeof a === 'object' && typeof b === 'object') {
            return Object.keys(a).every((key) => isEqual(a[key], b[key]));
        }
        return Object.is(a, b);
    };
    return arr.reduce((accumulator, current) => {
        if (accumulator.findIndex(item => isEqual(current, item)) === -1) {
            accumulator.push(current);
        }
        return accumulator;
    }, []);
}

[yijinc]

    const isEqual = (a, b) => {
        if (Array.isArray(a) && Array.isArray(b)) {
            return a.every((item, index) => isEqual(item, b[index]));
        }
        if (typeof a === 'object' && typeof b === 'object') {
            return Object.keys(a).every((key) => isEqual(a[key], b[key]));
        }
        return Object.is(a, b);
    };

isEqual 的判断有问题，当第二个变量多于第一个时，判断出错，如
isEqual([0, 1], [0, 1, 2]) === true

需要加个length 先判断

const isEqual = (a, b) => {
        if (Array.isArray(a) && Array.isArray(b)) {
            return a.length === b.length ? a.every((item, index) => isEqual(item, b[index])) : false;
        }
        if (typeof a === 'object' && typeof b === 'object') {
            return Object.keys(a).length === Object.keys(b).length ? Object.keys(a).every((key) => isEqual(a[key], b[key])) : false;
        }
        return Object.is(a, b);
};