/
printListNodeReverse.go
116 lines (95 loc) · 2.08 KB
/
printListNodeReverse.go
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package list
import (
"fmt"
)
type ListNode struct {
Val int
Next *ListNode
}
type ReversePrintListNode func(node *ListNode)
// 该函数是实现从尾到头打印链表 —— 剑指offer 面试题六
// 一般从头到尾打印链表,直接遍历就行。这里若反向打印一般思路是先反转,或者遍历入堆,再pop堆打印即可。
// 递归打印
func ReversePrintListNodeRecursion(header *ListNode) {
if header == nil {
return
}
ReversePrintListNodeRecursion(header.Next)
fmt.Println(header.Val)
}
// 循环遍历打印
func ReversePrintListNodeTraverse(header *ListNode) {
var last *ListNode
for cur := header; last != header; cur = header {
for cur.Next != last {
cur = cur.Next
}
fmt.Println(cur.Val)
last = cur
}
}
// 先反转再打印
func ReversePrintListNodeReverse(header *ListNode) {
var pre *ListNode
if header == nil {
return
}
next := header.Next
for next != nil {
header.Next = pre
pre = header
header = next
next = next.Next
}
header.Next = pre
for header != nil {
fmt.Println(header.Val)
header = header.Next
}
}
// 递归反转打印
func ReversePrintListNodeRecursionReverse(header *ListNode) {
header = recursionReverse(nil, header)
for header != nil {
fmt.Println(header.Val)
header = header.Next
}
}
func recursionReverse(pre, header *ListNode) *ListNode {
if header == nil {
return pre
}
next := header.Next
header.Next = pre
return recursionReverse(header, next)
}
// 堆栈打印
func ReversePrintListNodeHeap(header *ListNode) {
heap := new(myHeap)
for header != nil {
heap.Push(header)
header = header.Next
}
for heap.Len() > 0 {
cur := heap.Pop()
node := cur.(*ListNode)
fmt.Println(node.Val)
}
}
type myHeap []*ListNode
func (h *myHeap) Less(i, j int) bool {
return (*h)[i].Val < (*h)[j].Val
}
func (h *myHeap) Swap(i, j int) {
(*h)[i], (*h)[j] = (*h)[j], (*h)[i]
}
func (h *myHeap) Len() int {
return len(*h)
}
func (h *myHeap) Pop() (v interface{}) {
*h, v = (*h)[:h.Len()-1], (*h)[h.Len()-1]
return
}
func (h *myHeap) Push(v interface{}) {
*h = append(*h, v.(*ListNode))
}