Global scope isn't updated when new function (or class) is defined

[ssche]

Is there anything that can be done to allow the global namespace to be updated automatically? In (unrestricted) Python, function example() would have access to c, but in restricted python one is required to use global. In another example using metaclass, I tried to update globals()[name] = ob to allow classes to be available, but this didn't work (so I assume the same problem would apply for new functions).

Any idea would be appreciated.

from RestrictedPython import compile_restricted
from RestrictedPython import safe_globals

source_code = """

def c():
    return 1

def example():
    # required:
    # global c
    return c()

example()
"""

loc = {}
byte_code = compile_restricted(source_code, '<inline>', 'exec')
exec(byte_code, safe_globals, loc)

print (loc)

[kevinyang372]

Is there any update on this issue? I am also getting stuck on using restrictedpython to compile recursive functions as they are not added to the globals

[d-maurer]

Is there any update on this issue? I am also getting stuck on using restrictedpython to compile recursive functions as they are not added to the globals

Unlike @icemac, I do not think this is a bug. In my view, you get what you called for.
You call for the execution of your source (defining c and example) with globals safe_globals and locals loc. The definitions are put into loc which is not the __globals__ of function example; as a consequence, example cannot access c.

If you want to use loc as "globals", you could achieve this via:

loc = safe_globals.copy()
exec(byte_code, loc)

[kevinyang372]

@d-maurer Thank you! That does answer my question.