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2455.可被三整除的偶数的平均值.html
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2455.可被三整除的偶数的平均值.html
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta http-equiv="X-UA-Compatible" content="IE=edge" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<title>2455. 可被三整除的偶数的平均值</title>
</head>
<body>
<script>
// https://leetcode.cn/problems/average-value-of-even-numbers-that-are-divisible-by-three/
// 给你一个由正整数组成的整数数组 nums ,返回其中可被 3 整除的所有偶数的平均值。
// 注意:n 个元素的平均值等于 n 个元素 求和 再除以 n ,结果 向下取整 到最接近的整数。
//
// 提示:
// 1 <= nums.length <= 1000
// 1 <= nums[i] <= 1000
/**
* @param {number[]} nums
* @return {number}
*/
var averageValue = function (nums) {};
// --- answer-1 ---
// 6的倍数
var averageValue = function (nums = []) {
let num = 0;
let sum = 0;
for (const n of nums) {
if (n % 6 === 0) {
num += 1;
sum += n;
}
}
return num && Math.floor(sum / num);
};
// --- answer-1 ---
// --- answer-2 ---
// --- answer-2 ---
var nums = [1, 3, 6, 10, 12, 15];
var result = 9;
// 解释:6 和 12 是可以被 3 整除的偶数。(6 + 12) / 2 = 9 。
var nums = [1, 2, 4, 7, 10];
var result = 0;
// 解释:不存在满足题目要求的整数,所以返回 0 。
console.log('nums = ', nums);
console.log('result = ', result);
console.log('averageValue = ', averageValue(nums));
</script>
</body>
</html>