texmanager doesn't handle list of names for font.family

lib/matplotlib/backends/backend_ps.py

@@ -659,7 +659,7 @@ def draw_tex(self, gc, x, y, s, prop, angle, ismath='TeX!', mtext=None):
         color = '%1.3f,%1.3f,%1.3f'% gc.get_rgb()[:3]
         fontcmd = {'sans-serif' : r'{\sffamily %s}',
                'monospace'  : r'{\ttfamily %s}'}.get(
-                rcParams['font.family'], r'{\rmfamily %s}')
+                rcParams['font.family'][0], r'{\rmfamily %s}')
         s = fontcmd % s
         tex = r'\color[rgb]{%s} %s' % (color, s)
 

lib/matplotlib/font_manager.py

@@ -805,7 +805,9 @@ def set_family(self, family):
         """
         Change the font family.  May be either an alias (generic name
         is CSS parlance), such as: 'serif', 'sans-serif', 'cursive',
-        'fantasy', or 'monospace', or a real font name.
+        'fantasy', or 'monospace', a real font name or a list of real
+        font names.  Real font names are not supported when
+        `text.usetex` is `True`.
         """
         if family is None:
             family = rcParams['font.family']
@@ -1064,9 +1066,9 @@ def score_family(self, families, family2):
                 options = [x.lower() for x in options]
                 if family2 in options:
                     idx = options.index(family2)
-                    return 0.1 * (float(idx) / len(options))
+                    return 0.1 * ((float(idx) / len(options)) + float(i))
             elif family1 == family2:
-                return 0.0
+                return 0.1 * float(i)
         return 1.0
 
     def score_style(self, style1, style2):

lib/matplotlib/pyplot.py

@@ -278,11 +278,13 @@ def xkcd():
         # This figure will be in regular style
         fig2 = plt.figure()
     """
+    if rcParams['text.usetex']:
+        raise RuntimeError("xkcd mode is not compatible with text.usetex = True")
+
     from matplotlib import patheffects
     context = rc_context()
     try:
-        rcParams['text.usetex'] = False
-        rcParams['font.family'] = 'Humor Sans'
+        rcParams['font.family'] = ['Humor Sans', 'Comic Sans MS']
         rcParams['font.size'] = 14.0
         rcParams['path.sketch'] = (1, 100, 2)
         rcParams['path.effects'] = [

lib/matplotlib/texmanager.py

@@ -166,13 +166,15 @@ def __init__(self):
                  'available'))
 
         mkdirs(self.texcache)
-        ff = rcParams['font.family'].lower()
-        if ff in self.font_families:
-            self.font_family = ff
+        ff = rcParams['font.family']
+        if len(ff) == 1 and ff[0].lower() in self.font_families:
+            self.font_family = ff[0].lower()
         else:
-            mpl.verbose.report('The %s font family is not compatible with '
-                               'LaTeX. serif will be used by default.' % ff,
-                               'helpful')
+            mpl.verbose.report(
+                'font.family must be one of (%s) when text.usetex is True. '
+                'serif will be used by default.' %
+                   ', '.join(self.font_families),
+                'helpful')
             self.font_family = 'serif'
 
         fontconfig = [self.font_family]

matplotlibrc.template

@@ -101,7 +101,8 @@ backend      : %(backend)s
 # 'sans-serif' (e.g., Helvetica), 'cursive' (e.g., Zapf-Chancery),
 # 'fantasy' (e.g., Western), and 'monospace' (e.g., Courier).  Each of
 # these font families has a default list of font names in decreasing
-# order of priority associated with them.
+# order of priority associated with them.  When text.usetex is False,
+# font.family may also be one or more concrete font names.
 #
 # The font.style property has three values: normal (or roman), italic
 # or oblique.  The oblique style will be used for italic, if it is not