Wait for subprocess and exit with same return code

[mcg1969]

Fixes #154.
Rebases #158; original text from there:

---

Not sure how this made it through this long, but the current behavior is a pretty awful experience: random interleaved outputs (#154), broken usage when scripted, and failures not being caught.

Can work up a proper test if necessary... basically a project file like:

commands:
  a:
    windows: timeout 1 && echo a
  b:
    windows: echo b

then

anaconda-project run a
anaconda-project run b

would yield

b # immediately
a # after a second

and should yield

a # after a second
b # immediately

[bollwyvl]

I probably can't update on this, but it looks like this might do the trick:

def mock_popen(args, env, cwd, shell):
    executed['args'] = args
    executed['env'] = env
    executed['cwd'] = cwd
    executed['shell'] = shell

    class MockProcess(object):
        def wait(self):
            return 0

    return MockProcess()

[mcg1969]

Thanks Nick!

[bollwyvl]

Godspeed! Thanks for picking up all these pieces: I've been using project a lot and this is really the only thing I've had to maintain a patch for.

[mcg1969]

That's great to hear. It has several internal fans as well and it was high time it got the love it deserves.

[bollwyvl]

Hooray!