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%%sql postgresql:///oldestbusinesses

1.Select the oldest and newest founding years from the businesses table SELECT MIN(year_founded),MAX(year_founded) FROM businesses;

  1. Get the count of rows in businesses where the founding year was before 1000

SELECT COUNT(*) FROM businesses WHERE year_founded < 1000;

  1. Select all columns from businesses where the founding year was before 1000 Arrange the results from oldest to newest

SELECT * FROM businesses WHERE year_founded < 1000 ORDER BY year_founded;

4.Select business name, founding year, and country code from businesses; and category from categories where the founding year was before 1000, arranged from oldest to newest

SELECT businesses.business, businesses.year_founded, businesses.country_code, categories.category FROM businesses INNER JOIN categories ON businesses.category_code = categories.category_code WHERE businesses.year_founded < 1000 ORDER BY businesses.year_founded ASC;

5.Select the category and count of category (as "n") arranged by descending count, limited to 10 most common categories

SELECT categories.category, COUNT(categories.category) AS n FROM categories INNER JOIN businesses ON categories.category_code = businesses.category_code GROUP BY categories.category ORDER BY n DESC LIMIT 10;

6.Select the oldest founding year (as "oldest") from businesses, and continent from countries for each continent, ordered from oldest to newest

SELECT countries.continent, MIN(businesses.year_founded) AS oldest FROM businesses INNER JOIN countries ON businesses.country_code = countries.country_code GROUP BY countries.continent ORDER BY oldest ASC;

7.Select the business, founding year, categories.category, country, and continent

SELECT businesses.business, businesses.year_founded, categories.category, countries.country, countries.continent FROM businesses INNER JOIN categories ON businesses.category_code = categories.category_code INNER JOIN countries ON businesses.country_code = countries.country_code;

8.Count the number of businesses in each continent and category

SELECT countries.continent, categories.category, COUNT(businesses.business) AS n FROM businesses INNER JOIN categories ON businesses.category_code = categories.category_code INNER JOIN countries ON businesses.country_code = countries.country_code GROUP BY countries.continent, categories.category;

9.Repeat that previous query, filtering for results having a count greater than 5

SELECT countries.continent, categories.category, COUNT(businesses.business) AS n FROM businesses INNER JOIN categories ON businesses.category_code = categories.category_code INNER JOIN countries ON businesses.country_code = countries.country_code GROUP BY countries.continent, categories.category HAVING COUNT(businesses.business) > 5 ORDER BY n DESC;

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