Changing the name of the output file

[rsomani95]

This issue was raised before here, but got closed prematurely.

I wanted to know if there is any way that we can have control over the name of the output image. While I understand there are reasons why the filename is the way it is from your explanation in the previous issue, it would save me a lot of time and resources if I could change the output name.

Thanks!

[Belval]

Would you mind describing your process? You can access the filename using Image.filename and every image has a _X suffix where X is the page number.

Don't get me wrong, I am not completely closed to the idea, I simply have trouble picturing a legitimate scenario.

[rsomani95]

Would you mind describing your process?

Sure, I'm working on a data visualisation project where I prepare the data in Python, run it using Processing on the Terminal, but in order to run it in headless mode, I need to export it to PDF as that's the only case where I can automate the process (I'm working on macOS, there are better solutions for Linux OS). I need to use pdf2image to convert these PDFs back to JPEGs as I'd like to put these together sequentially in a video editor.
Thus, naming them correctly is crucial.

You can access the filename using Image.filename and every image has a _X suffix where X is the page number.

Thank you. I realised I was making the silly error of accessing the list itself, and not the element of the list.
Here's the code for anyone facing a similar issue:

img = convert_from_path(pdf_path = proc_path[0], output_folder = out_path, fmt = 'jpg') img.filename #gives an error: 'list' object has no attribute 'filename'
img[0].filename does the trick.