Skip to content

Commit

Permalink
sage: Normalize sign of polynomial factors in prover
Browse files Browse the repository at this point in the history
The prover, when run on recent sage versions,  failed to prove some of its
goals due to a change in sage. This commit adapts our code accordingly.
The prover passes again after this commit.
  • Loading branch information
real-or-random committed Feb 4, 2022
1 parent eae7586 commit 77cfa98
Showing 1 changed file with 34 additions and 10 deletions.
44 changes: 34 additions & 10 deletions sage/group_prover.sage
Expand Up @@ -177,6 +177,30 @@ class constraints:
def __repr__(self):
return "%s" % self

def normalize_factor(p):
"""Normalizes the sign of primitive polynomials (as returned by factor())
This function ensures that the polynomial has a positive leading coefficient.
This is necessary because recent sage versions (starting with v9.3 or v9.4,
we don't know) are inconsistent about the placement of the minus sign in
polynomial factorizations:
```
sage: R.<ax,bx,ay,by,Az,Bz,Ai,Bi> = PolynomialRing(QQ,8,order='invlex')
sage: R((-2 * (bx - ax)) ^ 1).factor()
(-2) * (bx - ax)
sage: R((-2 * (bx - ax)) ^ 2).factor()
(4) * (-bx + ax)^2
sage: R((-2 * (bx - ax)) ^ 3).factor()
(8) * (-bx + ax)^3
```
"""
# Assert p is not 0 and that its non-zero coeffients are coprime.
# (We could just work with the primitive part p/p.content() but we want to be
# aware if factor() does not return a primitive part in future sage versions.)
assert p.content() == 1
# Ensure that the first non-zero coefficient is positive.
return p if p.lc() > 0 else -p

def conflicts(R, con):
"""Check whether any of the passed non-zero assumptions is implied by the zero assumptions"""
Expand Down Expand Up @@ -204,10 +228,10 @@ def get_nonzero_set(R, assume):
nonzero = set()
for nz in map(numerator, assume.nonzero):
for (f,n) in nz.factor():
nonzero.add(f)
nonzero.add(normalize_factor(f))
rnz = zero.reduce(nz)
for (f,n) in rnz.factor():
nonzero.add(f)
nonzero.add(normalize_factor(f))
return nonzero


Expand All @@ -222,27 +246,27 @@ def prove_nonzero(R, exprs, assume):
return (False, [exprs[expr]])
allexprs = reduce(lambda a,b: numerator(a)*numerator(b), exprs, 1)
for (f, n) in allexprs.factor():
if f not in nonzero:
if normalize_factor(f) not in nonzero:
ok = False
if ok:
return (True, None)
ok = True
for (f, n) in zero.reduce(allexprs).factor():
if f not in nonzero:
if normalize_factor(f) not in nonzero:
ok = False
if ok:
return (True, None)
ok = True
for expr in exprs:
for (f,n) in numerator(expr).factor():
if f not in nonzero:
if normalize_factor(f) not in nonzero:
ok = False
if ok:
return (True, None)
ok = True
for expr in exprs:
for (f,n) in zero.reduce(numerator(expr)).factor():
if f not in nonzero:
if normalize_factor(f) not in nonzero:
expl.add(exprs[expr])
if expl:
return (False, list(expl))
Expand Down Expand Up @@ -279,17 +303,17 @@ def describe_extra(R, assume, assumeExtra):
if base not in zero:
add = []
for (f, n) in numerator(base).factor():
if f not in nonzero:
add += ["%s" % f]
if normalize_factor(f) not in nonzero:
add += ["%s" % normalize_factor(f)]
if add:
ret.add((" * ".join(add)) + " = 0 [%s]" % assumeExtra.zero[base])
# Iterate over the extra nonzero expressions
for nz in assumeExtra.nonzero:
nzr = zeroextra.reduce(numerator(nz))
if nzr not in zeroextra:
for (f,n) in nzr.factor():
if zeroextra.reduce(f) not in nonzero:
ret.add("%s != 0" % zeroextra.reduce(f))
if normalize_factor(zeroextra.reduce(f)) not in nonzero:
ret.add("%s != 0" % normalize_factor(zeroextra.reduce(f)))
return ", ".join(x for x in ret)


Expand Down

0 comments on commit 77cfa98

Please sign in to comment.