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Add day 9
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MadhavBahl committed Jan 1, 2019
1 parent f7ca66e commit 24ae28a
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6 changes: 6 additions & 0 deletions Day1/README.md
Expand Up @@ -381,3 +381,9 @@ for i in range(1,n+1):
else:
print(i)
```

### Have Another solution?

The beauty of programming lies in the fact that there is never a single solution to any problem.

In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)
6 changes: 6 additions & 0 deletions Day2/README.md
Expand Up @@ -771,3 +771,9 @@ def palindrome(str)
str != nil and str === short_solution(str)
end
```

### Have Another solution?

The beauty of programming lies in the fact that there is never a single solution to any problem.

In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)
6 changes: 6 additions & 0 deletions Day3/README.md
Expand Up @@ -366,3 +366,9 @@ print("number of characters not matching are:",len(k))

The #1 reason for not being successful is inconsistency, and it is a common trend that people start something and on give up on the third day itself, and one of the major reasons behind that is that they find it difficult to continue. 
So, to keep everyone (who is following the DailyCodes challenge) consistent, I have decided to keep today's question very simple and straightforward.

### Have Another solution?

The beauty of programming lies in the fact that there is never a single solution to any problem.

In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)
6 changes: 6 additions & 0 deletions day4/README.md
Expand Up @@ -888,3 +888,9 @@ str = gets
str.chomp!
puts "The most frequent character in #{str} is : #{most_frequent_character(str)}"
```

### Have Another solution?

The beauty of programming lies in the fact that there is never a single solution to any problem.

In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)
6 changes: 6 additions & 0 deletions day5/README.md
Expand Up @@ -2158,3 +2158,9 @@ int main() {
return 0;
}
```
### Have Another solution?
The beauty of programming lies in the fact that there is never a single solution to any problem.
In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)
6 changes: 6 additions & 0 deletions day6/README.md
Expand Up @@ -1097,3 +1097,9 @@ first_str = gets().chomp
second_str = gets().chomp
puts "\nAre #{first_str} and #{second_str} anagrams? #{check_anagram(String.new(first_str), String.new(second_str))}"
```

### Have Another solution?

The beauty of programming lies in the fact that there is never a single solution to any problem.

In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)
8 changes: 7 additions & 1 deletion day7/README.md
Expand Up @@ -866,4 +866,10 @@ def main
end

main
```
```

### Have Another solution?

The beauty of programming lies in the fact that there is never a single solution to any problem.

In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)
6 changes: 6 additions & 0 deletions day8/README.md
Expand Up @@ -281,3 +281,9 @@ public class Levenshtein {
}
}
```

### Have Another solution?

The beauty of programming lies in the fact that there is never a single solution to any problem.

In case you have an alternative way to solve this problem, do contribute to this repository (https://github.com/CodeToExpress/dailycodebase) :)

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