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A framework that use one line of code to solve hex or decimal multifarious data transformation problem

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CoderLSWang/LSUDPDataDetail

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LSUDPDataDetail

A framework that use one line of code to solve hex or decimal multifarious data transformation problem when a UDP or TCP communications.

一个在UDP或TCP通信时,16进制、10进制、NSData等数据之间的转换发送等工具处理类库

UDP指令里面包含通信的地址,设备Id,发送的数据等具体指令协议解读,以及16进制、10进制、NSData等之间的转换,请查看Demo,或者参阅 我的博客

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一. Installation 安装

  • CocoaPods:pod 'LSUDPDataDetail'
  • 手动导入:将LSUDPDataDetail文件夹拽入项目中,导入头文件:#import "LSUDPDataDetail.h"

二. Example 例子

//指令的发送
- (void)sendCombustibleGasCommand
{
    //address:333333333333333303d0
    //Node address of the smart devices and sensors is not binding, if a sensor node chassis changed, then the sensor's address has changed
    //智能设备中的节点地址和传感器不是绑定一起的,如果某个传感器的节点底盘换了,那么这个传感器的地址也换了,所以这里是动态的

    NSString *addressHexStr = @"333333333333333303d0";
    NSData *addressData = [LSUDPDataDetail commandByteDataFromHexString:addressHexStr];
    [self combustibleGasCommandData:addressData];

}

//The data of nodes will coming here , if u want to control node (smart home/sensor), u need to get the address of the node (device).This address is get from here.And sensor data is also get from here.
//节点发过来的数据都会来到这里,控制节点(智能家居/传感器)需要拿到节点的地址(设备刚入网的时候),便是在这里获取。读取传感器发过来的采集到的数据也是在这里获取

- (void)udpSocket:(GCDAsyncUdpSocket *)sock didReceiveData:(NSData *)data
fromAddress:(NSData *)address
withFilterContext:(nullable id)filterContext
{

    //Selection of sensors, when the equipment send collectd data / 设备发送来采集的数据时,对传感器的甄选

    NSString *commandHexStr = [LSUDPDataDetail getHexStringFromData:data withRange:NSMakeRange(2, 6)];
    if ([commandHexStr isEqualToString:@"545243"]) {//TRC :The command header / 命令头
    NSLog(@"dataHexStr = %@",dataHexStr);
    }

}

三. Requirements 要求

iOS7及以上系统可使用. ARC环境.

四. More 更多

If you find a bug, please create a issue.
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More infomation please view demo.
如果你发现了bug,请提一个issue。
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A framework that use one line of code to solve hex or decimal multifarious data transformation problem

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