problem 30, safeguard in new-problem.py

Problems/028/solution.py

@@ -1,8 +1,5 @@
 #!/usr/bin/python3
 
-import os, sys
-sys.path.append(os.getcwd())
-
 def main():
     # think of the spiral as a set of nested squares, where the side length grows
     # o-n every level by two (one integer on each side). then we try to capture all

Problems/029/solution.py

@@ -1,9 +1,11 @@
 #!/usr/bin/python3
 
-import os, sys
-sys.path.append(os.getcwd())
-
 def main():
+    sequence = set([])
+    for a in range(2,101):
+        for b in range(2,101):
+            sequence.add(a**b)
+    return len(sequence)
 
 if __name__=='__main__':
     print(main())

Problems/030/solution.py

@@ -0,0 +1,24 @@
+#!/usr/bin/python3
+
+import os, sys
+sys.path.append(os.getcwd())
+
+def main():
+    # note that 9^5 = 59,049. So the maximum sum of digits to the fifth power,
+    # for a four-digit number, for example, is 4 * 9^5 = 236,196. For a seven-digit
+    # number, however, 7 * 9^5 = 413,343, which is smaller than the smallest seven-digit number.
+    # so this suggests we only need to check through the six-digit-numbers, where
+    # the largest possible such number is 6 * 9^5 = 354,294.
+
+    accumulator = 0
+    # start the range at 10. according to the problem, single-digit numbers do not create sums,
+    # which i disagree with, but so be it.
+    for i in range(10, 354295):
+        fifth_digit_sum = sum(int(c)**5 for c in str(i))
+        if fifth_digit_sum == i:
+            accumulator += i
+
+    return accumulator
+
+if __name__=='__main__':
+    print(main())

Problems/031/solution.py

@@ -0,0 +1,9 @@
+#!/usr/bin/python3
+
+import os, sys
+sys.path.append(os.getcwd())
+
+def main():
+
+if __name__=='__main__':
+    print(main())

confirm-solutions.py

@@ -36,7 +36,11 @@
     "023": 4179871,
     "024": "2783915460",
     "025": 4782,
-    "026": 983
+    "026": 983,
+    "027": -59231,
+    "028": 669171001,
+    "029": 9183,
+    "030": 443839,
 
 }
 

new-problem.py

@@ -6,6 +6,8 @@
 
 if not os.path.exists(new_problem):
     os.mkdir(new_problem)
+else:
+    raise IOError("Error! Path `{}` already exists. Exiting.".format(new_problem))
 
 filetext = ["#!/usr/bin/python3\n", "\n", "import os, sys\n", "sys.path.append(os.getcwd())\n",
             "\n", "def main():\n", "\n", "if __name__=='__main__':\n", "    print(main())\n"]