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MaxNestingDepthOfParentheses.kt
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MaxNestingDepthOfParentheses.kt
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import java.util.Stack
import kotlin.math.max
/*
* Maximum Nesting Depth of the Parentheses
A string is a valid parentheses string (denoted VPS) if it meets one of the following:
It is an empty string "", or a single character not equal to "(" or ")",
It can be written as AB (A concatenated with B), where A and B are VPS's, or
It can be written as (A), where A is a VPS.
We can similarly define the nesting depth depth(S) of any VPS S as follows:
depth("") = 0
depth(C) = 0, where C is a string with a single character not equal to "(" or ")".
depth(A + B) = max(depth(A), depth(B)), where A and B are VPS's.
depth("(" + A + ")") = 1 + depth(A), where A is a VPS.
For example, "", "()()", and "()(()())" are VPS's (with nesting depths 0, 1, and 2), and ")(" and "(()" are not VPS's.
Given a VPS represented as string s, return the nesting depth of s.
Example 1:
Input: s = "(1+(2*3)+((8)/4))+1"
Output: 3
Explanation: Digit 8 is inside of 3 nested parentheses in the string.
Example 2:
Input: s = "(1)+((2))+(((3)))"
Output: 3
Constraints:
1 <= s.length <= 100
s consists of digits 0-9 and characters '+', '-', '*', '/', '(', and ')'.
It is guaranteed that parentheses expression s is a VPS.
*/
fun main() {
print(maxDepth("(1+(2*3)+((8)/4))+1"))
}
fun maxDepth(s: String): Int {
var depth = 0
var maxCounter = 0
for (ch in s) {
when (ch) {
'(' -> depth++
')' -> depth--
}
maxCounter = max(depth, maxCounter)
}
return maxCounter
}
class Solution {
fun maxDepth(s: String): Int {
var output = 0
var count = 0
s.forEach { c ->
if (c == '(') {
count++
} else if (c == ')') {
output = max(output, count)
count--
}
}
return output
}
}
class Solution {
fun maxDepth(s: String): Int {
var max = 0;
var counter = 0;
for (c in s) {
when (c) {
'(' -> counter++
')' -> {
max = max(max, counter)
counter--
}
}
}
return max
}
}
class Solution {
fun maxDepth(s: String): Int {
if (s.isEmpty() || (s.length == 1 && s != "(" && s != ")")) return 0
var resultDepth = 0
val stack = Stack<Char>()
var tmpCount = 0
s.forEach {
when (it) {
'(' -> {
if (stack.isEmpty()) {
tmpCount = 0
}
tmpCount++
stack.push(it)
}
')' -> {
if (stack.isEmpty()) return 0
stack.pop()
resultDepth = max(resultDepth, tmpCount)
if (!stack.isEmpty()) {
tmpCount = stack.size
}
}
}
}
return resultDepth
}
}
class Solution {
fun maxDepth(s: String): Int {
var res = 0
val stack = Stack<Char>()
for (c in s) {
if (c != '(' && c != ')')
continue
if (c == '(') {
stack.push(c)
res = maxOf(res, stack.size)
} else if (stack.isNotEmpty()) {
stack.pop()
}
}
return res
}
}