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Should be handled by parsing the link headers, and following the data they provide.
Seem to be able to get reasonably robust first-effort results from:
r, c = req_get(page) m = re.findall('<(?P<url>.*?)>; rel="(?P<rel>.*?)"', r['Link'])
Clearly, a proper solution should be saner than that. If/when hubugs comes off the back burner...
hubugs
The text was updated successfully, but these errors were encountered:
See 0a983aa. Thanks Matt, but even your commit message admits it needs to be better.
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Should be handled by parsing the link headers, and following the data they provide.
Seem to be able to get reasonably robust first-effort results from:
Clearly, a proper solution should be saner than that. If/when
hubugs
comes off the back burner...The text was updated successfully, but these errors were encountered: