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[BUG] JSQLParser 4.6 : Cassandra : No table to parse map data type select query #1757

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devanshusharma17 opened this issue Apr 3, 2023 · 1 comment · Fixed by #1778
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@devanshusharma17
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devanshusharma17 commented Apr 3, 2023

Always check against the Latest SNAPSHOT of JSQLParser and the Syntax Diagram

Failing SQL Feature:

  • I am trying to parse Cassandra's query with the Map data type. It is not able to parse.

SQL Example:

  • Basic select query with Map data type
    -- Replace with your ACTUAL example
    SELECT my_map['my_key'] FROM my_table WHERE id = 123;
    SELECT cast(my_map['my_key'] as int) FROM my_table WHERE id = 123;

Software Information:

  • JSqlParser version: 4.6
  • Cassandra's

Tips:

Please write in English and avoid Screenshots (as we can't copy and paste content from it).
Try your example online with the latest JSQLParser and share the link in the error report.
Do provide Links or References to the specific Grammar and Syntax you are trying to use.

@manticore-projects
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Greetings.

Definitely unsupported since JSQLParser is a SQL Parser while Casandra seems to be a NO-SQL database.
So unless you provide or sponsor an implementation, it's not in scope.

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