filter is deprecated, but does not give a deprecation warning

[dpsanders]

Using filter gives no deprecation warning:

  | | |_| | | | (_| |  |  Version 0.6.0-pre.beta.83 (2017-04-08 21:57 UTC)
 _/ |\__'_|_|_|\__'_|  |  Commit 965c938eb* (0 days old master)
|__/                   |  x86_64-apple-darwin16.0.0

julia> v = [1, 2, 3, 4, 5]
5-element Array{Int64,1}:
 1
 2
 3
 4
 5

julia> filter(x->x>3, v)
2-element Array{Int64,1}:
 4
 5

[yuyichao]

I don't think it's deprecated.

[yuyichao]

Ref #18839 (comment)

• I separated Base.filter and IterTools.filter into two functions (since the latter is lazy and the former is eager). This is up for debate.

[dpsanders]

As far as I understand, filter was moved to Iterators.filter:

https://github.com/JuliaLang/julia/blob/master/base/deprecated.jl#L383

[yuyichao]

See my comment above. Base.filter and Iterators.filter (IterTools.filter in the first version of the linked PR) are two different functions. The deprecation was only added so that the separated function can still be used from Base.filter with a depwarn. Other methods are NOT deprecated.

[dpsanders]

OK thanks.