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# From The Computer Language Benchmarks Game | ||
# http://shootout.alioth.debian.org/ | ||
# Contributed by Wesley Moxam | ||
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def fannkuch(n) | ||
sign, maxflips, sum = 1, 0, 0 | ||
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p = [nil].concat((1..n).to_a) | ||
q = p.dup | ||
s = p.dup | ||
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while(true) | ||
# Copy and flip. | ||
q1 = p[1] # Cache 1st element. | ||
if q1 != 1 | ||
q = p.dup | ||
flips = 1 | ||
while(true) | ||
qq = q[q1] | ||
if qq == 1 # ... until 1st element is 1. | ||
sum = sum + sign * flips | ||
maxflips = flips if flips > maxflips # New maximum? | ||
break | ||
end | ||
q[q1] = q1 | ||
if q1 >= 4 | ||
i, j = 2, q1 - 1 | ||
begin | ||
q[i], q[j] = q[j], q[i] | ||
i = i + 1 | ||
j = j - 1 | ||
end while i < j | ||
end | ||
q1 = qq | ||
flips = flips + 1 | ||
end | ||
end | ||
# Permute. | ||
if sign == 1 | ||
# Rotate 1<-2. | ||
p[1], p[2] = p[2], p[1] | ||
sign = -1 | ||
else | ||
# Rotate 1<-2 and 1<-2<-3. | ||
p[2], p[3] = p[3], p[2] | ||
sign = 1 | ||
3.upto(n) do |i| | ||
(s[i] = s[i] - 1) && break unless s[i] == 1 | ||
return [sum, maxflips] if i == n # Out of permutations. | ||
s[i] = i | ||
# Rotate 1<-...<-i+1. | ||
t = p[1] | ||
1.upto(i) do |j| | ||
p[j] = p[j+1] | ||
end | ||
p[i+1] = t | ||
end | ||
end | ||
end | ||
end | ||
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perf_test('fannkuch') { fannkuch(9) } |