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We should also decide whether to implement Base.isinf.
Base.isfinite has a default implementation of isfinite(x::Number) = iszero(x - x), which we currently delegate to -- this seems to be sensible. But we should add tests for this regardless.
The text was updated successfully, but these errors were encountered:
Note that the built-in Complex type is a good model for e.g. what should happen if one component of a multivector is Inf and the other is NaN -- we should simply return true from both isnan and isinf.
We should also decide whether to implement
Base.isinf
.Base.isfinite
has a default implementation ofisfinite(x::Number) = iszero(x - x)
, which we currently delegate to -- this seems to be sensible. But we should add tests for this regardless.The text was updated successfully, but these errors were encountered: