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type; closes #364
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rzach committed Feb 28, 2024
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is true for~$n$. We have $\Gamma_{n+1} = \Gamma_n \cup \{!A_n\}$ or $=
\Gamma_n \cup \{\lnot !A_n\}$ by construction. So $\Gamma_n \subseteq
\Gamma_{n+1}$. If $i < n$, then $\Gamma_i \subseteq \Gamma_n$ by
inductive hypothesis, and so $\subseteq \Gamma_{n+1}$ by transitivity
inductive hypothesis, and so $\Gamma_i \subseteq \Gamma_{n+1}$ by transitivity
of~$\subseteq$.

From this it follows that every finite subset of $\Gamma^*$ is a
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