Make the normalization operator more general and fix bug in l2_normalize. #11348
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1. Refine the raw norm_op and let it more general to support to normalize Tensor along any axis. 2. There is bug in l2_normalize API, which lacks of sqrt after . 3. Use norm_op to refine the l2_normalize API.
paddle/fluid/operators/norm_op.h
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| // y = x / sqrt((sum(x * x) + epsilon)) | ||
| // norm = sqrt(sum(x * x) + epsilon) | ||
| norm.device(*place) = norm + x_pow.eval().sum(rdim) + eps; |
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你这里是不是多加个eps? 在line 68 不是已经令out_norm=eps了么？
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Yeah, refine code here. Thanks! @wanghaoshuang
paddle/fluid/operators/norm_op.h
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| // dx = ( dy/sqrt(sum(x*x)) ) * [1 - x*sum(x) / sum(x*x)] | ||
| sum.device(*place) = (x * dy).sum(rdim); | ||
| dx.device(*place) = sum.reshape(rshape).broadcast(bcast) * x; | ||
| dx.device(*place) = dx / norm.pow(2).broadcast(bcast); |
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norm.pow(2) = sum(x*x) + eps ,但是我在你的公式里没有看到eps?
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I modify the above formula.
paddle/fluid/operators/norm_op.h
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| Eigen::DSizes<int, 3> bcast(1, n, 1); | ||
| Eigen::DSizes<int, 3> rshape(pre, 1, post); | ||
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| // dx = ( dy/sqrt(sum(x*x)) ) * [1 - x*sum(x) / sum(x*x)] |
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怎么感觉你这个公式和实际计算过程有diff？可以把每一步的计算标注下么？
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Thanks for so detailed review. I add comments.
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Fix #11345
Fix #7266