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Handle overflow cases #78
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There were overflow cases hidden in the encode and decode: 1. Encoding - Any number with the 31st bit set would be incorrect, because it used `>>` instead of `>>>`. So the 31st bit would be set to the 32nd (sign bit, making it negative). Then when we try to encode the number, we would that it's `num < 0` after the first iteration. 2. Decoding - The encoded representation of -2147483648 (smallest 32bit signed int) would return -0 - Any number with the 31st bit set would return the opposite sign, because it used `>>` instead of `>>>`.
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The test failure here is due to |
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Yeah, looking at that right now |
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Released 1.4.5. Thank you |
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There were overflow cases hidden in the encode and decode:
>>instead of>>>. So the 31st bit would be set to the 32nd (sign bit, making it negative). Then when we try to encode the number, we would that it'snum < 0after the first iteration.>>instead of>>>.