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While entering large number(999999999999990) it is showing wrong output #718

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sri95427 opened this issue Sep 15, 2021 · 1 comment
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@sri95427
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sri95427 commented Sep 15, 2021

Hi Team,
Actually we have a scenario, we need to enter large amount like "999999999999990" so in this case the output we are getting is wrong "999,999,999,999,990.13" .

Could you please suggest possible solution for this.

<!DOCTYPE html>
<html>
<body>
<head>
<script src="//cdnjs.cloudflare.com/ajax/libs/numeral.js/2.0.6/numeral.min.js"></script>
</head>

<script>
function myFunction(value){
return numeral(value).format('0,0.00')
}

document.getElementById("demo").innerHTML = myFunction(999999999999990); 
</script>

</body>
</html>

Output: 999,999,999,999,990.13

mhmdaminraeisi added a commit to mhmdaminraeisi/Numeral-js that referenced this issue Dec 20, 2021
mhmdaminraeisi added a commit to mhmdaminraeisi/Numeral-js that referenced this issue Dec 20, 2021
@hlwen
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hlwen commented Nov 4, 2023

Add the following code before executing

Number.prototype.toFixed = function (d) {
  var s = this + "";
  if (!d) d = 0;
  if (s.indexOf(".") == -1) s += ".";
  s += new Array(d + 1).join("0");
  if (new RegExp("^(-|\\+)?(\\d+(\\.\\d{0," + (d + 1) + "})?)\\d*$").test(s)) {
    var s = "0" + RegExp.$2,
      pm = RegExp.$1,
      a = RegExp.$3.length,
      b = true;
    if (a == d + 2) {
      a = s.match(/\d/g);
      if (parseInt(a[a.length - 1]) > 4) {
        for (var i = a.length - 2; i >= 0; i--) {
          a[i] = parseInt(a[i]) + 1;
          if (a[i] == 10) {
            a[i] = 0;
            b = i != 1;
          } else break;
        }
      }
      s = a.join("").replace(new RegExp("(\\d+)(\\d{" + d + "})\\d$"), "$1.$2");

    }
    if (b) s = s.substr(1);
    return (pm + s).replace(/\.$/, "");
  }
  return this + "";
}

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