Cohomology Ring of RP2 \/ S1 #883
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The index and the groups were at the same level. The should be at different one, for instance if the index is Nat, and the group something else
-> Modify some notions in gradedCommutativity -> new lemme for the "good" -h^ -> proof
-> Because this case is so degenerated, things compute. This new proof is forgetting some of the computation to have proof that will rise better to non-degenerated case
-> changing gradedComm by gradedCom' to account the previuous change
-> There is a need of the special as on the left we need the CommRing to take A / < a, ..., b > and we nedd a ring on the right as H*(X) is not a CommRing but a gradedComm Ring
-> A cleaner way to deal with the cup product -> Finish all the structure except some cases of the cup-product -> Prove the retraction property
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@mortberg Ready too. |
Co-authored-by: Anders Mörtberg <andersmortberg@gmail.com>
Co-authored-by: Anders Mörtberg <andersmortberg@gmail.com>
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Lots of conflicts here now, please rebase on master |
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Start computing the cohomology Ring of RP2 / S1