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String jsonStr = "{1:1}"; JSONObject jsonObject = JSONObject.parseObject(jsonStr); System.out.println(jsonObject.containsKey(1));//false System.out.println(jsonObject.get(1));//can get value
The text was updated successfully, but these errors were encountered:
bug fixed for JSONObject.containsKey with Number Key, for issue #3093
b67a747
https://github.com/alibaba/fastjson/releases/tag/1.2.68 问题已修复,请用新版本
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wenshao
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The text was updated successfully, but these errors were encountered: