Function template arguments are not shown

[leg0]

Given this code:

#include <utility>
static int s1;
static int s2;
std::pair<int const&, int const&> fun() { return std::make_pair(s1, s2);
}

The output is

#include <utility>

static int s1;
static int s2;

std::pair<const int &, const int &> fun()
{
  return std::pair<const int &, const int &>(std::make_pair(s1, s2));
}

But I expected to see:

#include <utility>

static int s1;
static int s2;

std::pair<const int &, const int &> fun()
{
  return std::pair<const int &, const int &>(std::make_pair<int, int>(s1, s2));
}

[andreasfertig]

Hello @leg0,

thanks for spotting and reporting this issue! I will look into it. I assume that the CallExpr does not consider the template arguments.

Andreas