runtime.Call keeps running continuations

[TheCount]

The doc for runtime.Call says:

func Call(t *Thread, f Value, args []Value, next Cont) error
Call calls f with arguments args, pushing the results on next. It may use the metamethod '__call' if f is not callable.

Actually, Call not only pushes the results of the call to f onto next, but proceeds running next and further continuations until nil or an error occurs.

I'm guessing this is the intended behavior, but I think that with this documentation and/or the name Call, this API is confusing, especially if seen in contrast to runtime.Call1, which has a more "expected" signature:

func Call1(t *Thread, f Value, args ...Value) (Value, error)

One possibility to make the API more intuitive would be to rename Call to something else (e. g. TailCall) and add a new Call API

func Call(t *Thread, f Value, args []Value, ret []Value) error

whose implementation would call the "old" Call with a termination for next.

What do you think?