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parabola.md

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The problem is in section Definition in How to Solve It:

Construct the point of intersection of a given straight line and a parabola which the focus and the directrix are given.

This is a Straightedge and Compass Construction problem. Although it is impossible to construct a parabola by straightedge and compass, the points of intersection can be found:

Construct a point P on the given straight line c at equal distances from the given point F and the given straight line d.

However, the solution is not given in this book. I'd like to give a coordinate solution, which can be converted to straightedge and compass construction.

Coordinate Solution

We put F onto the origin of Cartesian coordinates, then get the equations for P(x,y):

The solutions are:

Here let , then can be constructed by Geometric Mean Theorem.

Special Cases

There is only a tangent point if q = 0, and no intersection or tangent points if q < 0.

If c is a vertical line, then the equation for P(x,y) (x is the distance from F to c) is . The solution is .

Synthetic Solutions

Synthetic solutions can be found here.