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Hi Matt,
if the buffer is too small and value = ±inf/±(s)nan there will be buffer overflows again. Here:
using buffer_type = std::array<char, 2>;
value = -L::quiet_NaN();
std::bfloat16_t
(std , scientific) {} (2, Value too large for defined data type)
(boost, scientific) BOF! (9, Success)
(std , fixed ) {} (2, Value too large for defined data type)
(boost, fixed ) BOF! (9, Success)
(std , hex ) {} (2, Value too large for defined data type)
(boost, hex ) {} (2, Numerical result out of range)
(std , general ) {} (2, Value too large for defined data type)
(boost, general ) BOF! (9, Success)
regards
Gero
The text was updated successfully, but these errors were encountered:
Hi Matt,
if the buffer is too small and value = ±inf/±(s)nan there will be buffer overflows again. Here:
regards
Gero
The text was updated successfully, but these errors were encountered: