Can you refactor the source code?

[boratonAJ]

I need to restructure the source code and make it readable. Doing this will improve the quality of the program and optimize the design for agile programming.

SACEMA_Scientific_Task/script/wordfreq.py

Lines 38 to 41 in 5600b87

	#freq[''.join(char for char in word if char.isalnum())] += 1
	#print(freq)
	#del freq['']
	#fo = open(filename[:-3]+'freq', 'w')

SACEMA_Scientific_Task/script/wordfreq.py

Lines 45 to 50 in 5600b87

	# for word_ct in freq.most_common():
	# #my_file.write(word_ct[0] + ' ' + str(word_ct[1]) + '\n')
	# print(word_ct[0], word_ct[1])
	# #for word in sorted(freq.items(), key=freq.get, reverse=True):
	# #print(word, freq[word])
	# #fo.close()

SACEMA_Scientific_Task/script/wordfreq.py

Lines 58 to 75 in 5600b87

	#
	# if len(argv) == 1:
	# print('\n\tUsage:\t./wordfreq.py *.txt\n')
	# exit()
	#
	# #for filename in argv[1:]:
	# #freq = defaultdict(int)
	# #for line in open(filename, encoding='utf-8'):
	# #words = line.strip().lower().split(' ')
	# #for word in words:
	# #freq[''.join(char for char in word if char.isalnum())] += 1
	# #for word_ct in freq.most_common():
	# #print(word_ct[0], word_ct[1])
	# #for word in sorted(freq.items(), key=freq.get, reverse=True):
	# #print(word, freq[word])
	# #for word_count in sorted(freq.items(), key=lambda kv: kv[1])
	# #print(freq)
	#

[boratonAJ]

Refactoring completed!