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Extend Simulation For Convergence #30

Answered by BusyBeaver-42
seanlaw asked this question in Q&A
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$Q$ is an extremely special matrix

Short version

There are many solutions which achieve the maximal value. Eventhough the agents have no trouble reaching and staying in the solution space, the agents have trouble staying close to the same solution long enough for the convergence criterion to be met.

Long version

Let $a$, $b$, $c$, $d$ be four binary variables (that is variables in $\set{0, 1}$). Let $x = (a ~ b ~ c ~ d)^T$ and $y = (b ~ c ~ d)^T$. Define the following two matrices.

$$Q = \begin{pmatrix} 1 & 0 & 0 & 0 \\\ 0 & 0 & -0.5 & 0.5 \\\ 0 & -0.5 & 0 & 1 \\\ 0 & 0.5 & 1 & -2 \end{pmatrix}$$ $$P = \begin{pmatrix} 0 & -0.5 & 0.5 \\\ -0.5 & 0 & 1 \\\ 0.5 & 1 & -2 \end{pmatrix}$$

Matri…

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@seanlaw
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@seanlaw
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Answer selected by bqth29
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