fuck! missing code blocks makes highlighter sad

posts/2010-07-15-typeof-number-is-not-number.md

@@ -1,12 +1,15 @@
 How do you determine if a number is an integer in JavaScript?
 
+<code>
     x = 1;
 
     x === Math.floor(x);
     // returns true
+</code>
 
 But what happens if we try to add a method for this to the Number prototype?
 
+<code>
     Number.prototype.isInteger = function() {
       return this === Math.floor(this);
     }
@@ -15,20 +18,25 @@ But what happens if we try to add a method for this to the Number prototype?
 
     x.isInteger();
     // returns false!
+</code>
 
 Why? It turns out that when you add methods to Number, the type of the number inside the method becomes "object" rather than "number", but Math.floor returns a result of type "number". If you use the === operator, the two values are no longer equal because they're different types. So the method can be fixed two ways.
 
 Solution 1 is to avoid comparing types:
 
+<code>
     Number.prototype.isInteger = function() {
       return this == Math.floor(this);
       // works but breaks if you care about 0 vs other falsy values
     }
+</code>
 
 Solution 2 is better; cast "this" to the Number type and then the types are equal.
 
+<code>
     Number.prototype.isInteger = function() {
       return Number(this) === Math.floor(this);
     }
+</code>
 
 --- [@attaboy](http://twitter.com/attaboy)