Fix: Made arbitrary-return version use inout too

Swift's type inference gets really confused otherwise, erroring with “Ambiguous use of 'with(_:operations:)`”. Not sure why, but as before, having the args _exactly_ the same between all the overloads solves it.
capnslipp · Mar 6, 2020 · 5f14777 · 5f14777
1 parent b8336d2
commit 5f14777
Showing 1 changed file with 3 additions and 2 deletions.
diff --git a/Sources/With.swift b/Sources/With.swift
@@ -24,10 +24,11 @@ public func with<SubjectT:AnyObject>(_ subject:SubjectT, operations:(inout Subje
 
 /// “With” on an reference-type (object) subject, returning an aribitrary return value from the closure (the subject is still mutated).
 @inlinable
-public func with<SubjectT:AnyObject, ReturnT>(_ subject:SubjectT, operations:(SubjectT) throws -> ReturnT)
+public func with<SubjectT:AnyObject, ReturnT:Any>(_ subject:SubjectT, operations:(inout SubjectT) throws -> ReturnT)
 	rethrows -> ReturnT
 {
-	return try operations(subject)
+	var subject = subject
+	return try operations(&subject)
 }