Remove characters *#_^
for like statement
#1077
Closed
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当like语句中的值包含*#_^四个字符串时,最终拼成的语句会丢掉%符号,导致查询结果不正确,原始逻辑如下(line: 942):
if (!preg_match('/((?<!\\\)\[.+(?<!\\\)\]|(?<!\\\)[\*\?\!\%#^_]|%.+|.+%)/', $item)) { $item = '%' . $item . '%'; }