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using System; | ||
using System.Collections.Generic; | ||
using System.Linq; | ||
using System.Text; | ||
using Ckknight.ProjectEuler.Collections; | ||
|
||
namespace Ckknight.ProjectEuler.Problems | ||
{ | ||
[Problem(75, | ||
@"It turns out that 12 cm is the smallest length of wire that can be | ||
bent to form an integer sided right angle triangle in exactly one way, | ||
but there are many more examples. | ||
12 cm: (3,4,5) | ||
24 cm: (6,8,10) | ||
30 cm: (5,12,13) | ||
36 cm: (9,12,15) | ||
40 cm: (8,15,17) | ||
48 cm: (12,16,20) | ||
In contrast, some lengths of wire, like 20 cm, cannot be bent to form | ||
an integer sided right angle triangle, and other lengths allow more | ||
than one solution to be found; for example, using 120 cm it is possible | ||
to form exactly three different integer sided right angle triangles. | ||
120 cm: (30,40,50), (20,48,52), (24,45,51) | ||
Given that L is the length of the wire, for how many values of | ||
L <= 1,500,000 can exactly one integer sided right angle triangle be | ||
formed? | ||
Note: This problem has been changed recently, please check that you are | ||
using the right parameters.")] | ||
public class Problem075 : BaseProblem | ||
{ | ||
public override object CalculateResult() | ||
{ | ||
int maximum = 1500000; | ||
return new Range(1, int.MaxValue) | ||
.TakeWhile(m => 2 * m * m + 2 * m <= maximum) | ||
.SelectMany(m => new Range((m % 2 == 0) ? 1 : 2, m, 2) | ||
.Where(n => MathUtilities.AreRelativelyPrime(m, n)) | ||
.Select(n => 2 * m * m + 2 * m * n) | ||
.TakeWhile(l => l <= maximum)) | ||
.SelectMany(l => new Range(1, int.MaxValue) | ||
.Select(v => l * v) | ||
.TakeWhile(p => p <= maximum)) | ||
.ToMultiHashSet() | ||
.GetCounts() | ||
.Count(p => p.Value == 1); | ||
} | ||
} | ||
} |
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