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server: Don’t remove padding when performing RSA decryption
- RSA PKCS1v1.5 padding check is now performed on the Cloudflare Keyless SSL client.
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,136 @@ | ||
package rsa | ||
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import ( | ||
"crypto/rand" | ||
"crypto/rsa" | ||
"math/big" | ||
) | ||
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var bigZero = big.NewInt(0) | ||
var bigOne = big.NewInt(1) | ||
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func Decrypt(priv *rsa.PrivateKey, ciphertext []byte) ([]byte, error) { | ||
k := (priv.N.BitLen() + 7) / 8 | ||
if k < 11 { | ||
return nil, rsa.ErrDecryption | ||
} | ||
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c := new(big.Int).SetBytes(ciphertext) | ||
m, err := rsaDecryptInt(priv, c) | ||
if err != nil { | ||
return nil, err | ||
} | ||
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return leftPad(m.Bytes(), k), nil | ||
} | ||
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// rsaDecryptInt performs an RSA decryption on big.Ints, resulting in a | ||
// plaintext big.Int. RSA blinding is always used. | ||
func rsaDecryptInt(priv *rsa.PrivateKey, c *big.Int) (m *big.Int, err error) { | ||
// TODO(agl): can we get away with reusing blinds? | ||
if c.Cmp(priv.N) > 0 { | ||
err = rsa.ErrDecryption | ||
return | ||
} | ||
if priv.N.Sign() == 0 { | ||
return nil, rsa.ErrDecryption | ||
} | ||
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// Blinding enabled. Blinding involves multiplying c by r^e. | ||
// Then the decryption operation performs (m^e * r^e)^d mod n | ||
// which equals mr mod n. The factor of r can then be removed | ||
// by multiplying by the multiplicative inverse of r. | ||
var r, ir *big.Int | ||
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for { | ||
r, err = rand.Int(rand.Reader, priv.N) | ||
if err != nil { | ||
return | ||
} | ||
if r.Cmp(bigZero) == 0 { | ||
r = bigOne | ||
} | ||
var ok bool | ||
ir, ok = modInverse(r, priv.N) | ||
if ok { | ||
break | ||
} | ||
} | ||
bigE := big.NewInt(int64(priv.E)) | ||
rpowe := new(big.Int).Exp(r, bigE, priv.N) // N != 0 | ||
cCopy := new(big.Int).Set(c) | ||
cCopy.Mul(cCopy, rpowe) | ||
cCopy.Mod(cCopy, priv.N) | ||
c = cCopy | ||
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if priv.Precomputed.Dp == nil { | ||
m = new(big.Int).Exp(c, priv.D, priv.N) | ||
} else { | ||
// We have the precalculated values needed for the CRT. | ||
m = new(big.Int).Exp(c, priv.Precomputed.Dp, priv.Primes[0]) | ||
m2 := new(big.Int).Exp(c, priv.Precomputed.Dq, priv.Primes[1]) | ||
m.Sub(m, m2) | ||
if m.Sign() < 0 { | ||
m.Add(m, priv.Primes[0]) | ||
} | ||
m.Mul(m, priv.Precomputed.Qinv) | ||
m.Mod(m, priv.Primes[0]) | ||
m.Mul(m, priv.Primes[1]) | ||
m.Add(m, m2) | ||
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for i, values := range priv.Precomputed.CRTValues { | ||
prime := priv.Primes[2+i] | ||
m2.Exp(c, values.Exp, prime) | ||
m2.Sub(m2, m) | ||
m2.Mul(m2, values.Coeff) | ||
m2.Mod(m2, prime) | ||
if m2.Sign() < 0 { | ||
m2.Add(m2, prime) | ||
} | ||
m2.Mul(m2, values.R) | ||
m.Add(m, m2) | ||
} | ||
} | ||
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// Unblind. | ||
m.Mul(m, ir) | ||
m.Mod(m, priv.N) | ||
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return | ||
} | ||
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// modInverse returns ia, the inverse of a in the multiplicative group of prime | ||
// order n. It requires that a be a member of the group (i.e. less than n). | ||
func modInverse(a, n *big.Int) (ia *big.Int, ok bool) { | ||
g := new(big.Int) | ||
x := new(big.Int) | ||
y := new(big.Int) | ||
g.GCD(x, y, a, n) | ||
if g.Cmp(bigOne) != 0 { | ||
// In this case, a and n aren't coprime and we cannot calculate | ||
// the inverse. This happens because the values of n are nearly | ||
// prime (being the product of two primes) rather than truly | ||
// prime. | ||
return | ||
} | ||
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if x.Cmp(bigOne) < 0 { | ||
// 0 is not the multiplicative inverse of any element so, if x | ||
// < 1, then x is negative. | ||
x.Add(x, n) | ||
} | ||
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return x, true | ||
} | ||
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// leftPad returns a new slice of length size. The contents of input are right | ||
// aligned in the new slice. | ||
func leftPad(input []byte, size int) (out []byte) { | ||
n := len(input) | ||
if n > size { | ||
n = size | ||
} | ||
out = make([]byte, size) | ||
copy(out[len(out)-n:], input) | ||
return | ||
} |
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