BoundEdgeworth

This package implements the computation of the bounds described in the article Derumigny, Girard, and Guyonvarch (2021), Explicit non-asymptotic bounds for the distance to the first-order Edgeworth expansion, arxiv:2101.05780.

How to install

You can install the release version from the CRAN:

install.packages("BoundEdgeworth")

or the development version from GitHub:

# install.packages("remotes")
remotes::install_github("AlexisDerumigny/BoundEdgeworth")

Available bounds

Let $X_1, \dots, X_n$ be $n$ independent centered variables, and $S_n$ be their normalized sum, in the sense that $$S_n := \sum_{i=1}^n X_i / \text{sd} \Big(\sum_{i=1}^n X_i \Big).$$

The goal of this package is to compute values of $\delta_n > 0$ such that bounds of the form

$$ \sup_{x \in \mathbb{R}} \left| \textrm{Prob}(S_n \leq x) - \Phi(x) \right| \leq \delta_n, $$

or of the form

$$ \sup_{x \in \mathbb{R}} \left| \textrm{Prob}(S_n \leq x) - \Phi(x) - \frac{\lambda_{3,n}}{6\sqrt{n}}(1-x^2) \varphi(x) \right| \leq \delta_n, $$

are valid. Here $\lambda_{3,n}$ denotes the average skewness of the variables $X_1, \dots, X_n$.

The first type of bounds is returned by the function Bound_BE() (Berry-Esseen-type bound) and the second type (Edgeworth expansion-type bound) is returned by the function Bound_EE1().

Note that these bounds depends on the assumptions made on $(X_1, \dots, X_n)$ and especially on $K4$, the average kurtosis of the variables $X_1, \dots, X_n$. In all cases, they need to have finite fourth moment and to be independent. To get improved bounds, several additional assumptions can be added:

• the variables $X_1, \dots, X_n$ are identically distributed,
• the skewness (normalized third moment) of $X_1, \dots, X_n$ are all $0$, respectively.
• the distribution of $X_1, \dots, X_n$ admits a continuous component.

Example

setup = list(continuity = FALSE, iid = TRUE, no_skewness = FALSE)

Bound_EE1(setup = setup, n = 1000, K4 = 9)
#> [1] 0.1626857

This shows that

$$ \sup_{x \in \mathbb{R}} \left| \textrm{Prob}(S_n \leq x) - \Phi(x) - \frac{\lambda_{3,n}}{6\sqrt{n}}(1-x^2) \varphi(x) \right| \leq 0.1626857, $$

as soon as the variables $X_1, \dots, X_{1000}$ are i.i.d. with a kurtosis smaller than $9$.

Adding one more regularity assumption on the distribution of the $X_i$ helps to achieve a better bound:

setup = list(continuity = TRUE, iid = TRUE, no_skewness = FALSE)

Bound_EE1(setup = setup, n = 1000, K4 = 9, regularity = list(kappa = 0.99))
#> [1] 0.1214038

This shows that

$$ \sup_{x \in \mathbb{R}} \left| \textrm{Prob}(S_n \leq x) - \Phi(x) - \frac{\lambda_{3,n}}{6\sqrt{n}}(1-x^2) \varphi(x) \right| \leq 0.1214038, $$

in this case.